jQuery('input[name="preciof"].FormElement')

QuestionsjQuery('input[name="preciof"].FormElement')
pierremata asked 5 years ago

HEllo Abu, the next function  works only with the element “editable”, with “FormElement” doesn’t, why….

jQuery(‘input[name=”preciof”].editable’).val(Math.round(
parseFloat(jQuery(‘input[name=”precio”].editable’).val()) –
parseFloat(jQuery(‘input[name=”descuento”].editable’).val())
));

jQuery(‘input[name=”preciof”].FormElement’).val(Math.round(
parseFloat(jQuery(‘input[name=”precio”].FormElement’).val()) –
parseFloat(jQuery(‘input[name=”descuento”].FormElement’).val())
));

 

 

 

2 Answers
Abu Ghufran Staff answered 5 years ago

I am unable to generate this issue. I’ve prepared a working demo for you to compare with.

https://gist.github.com/gridphp/82a24aab26a7659f5585367c66678a12

Line: 45,53,87

_________________________
Abu Ghufran - Dev Team
Grid 4 PHP Framework
 
pierre mata answered 5 years ago

hello, i found a way to “skip” this error, if you change the name of the function, lets say “xxx”, works….

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